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131202222423479 is a prime number
BaseRepresentation
bin11101110101001111100101…
…110111000111110110110111
3122012112210212110121012121222
4131311033211313013312313
5114144104122420022404
61143013245140500555
736431022244535324
oct3565174567076667
9565483773535558
10131202222423479
1138894606139a39
121286ba529aa75b
135829416422a6c
14245831591db4b
151027d0e42edbe
hex7753e5dc7db7

131202222423479 has 2 divisors, whose sum is σ = 131202222423480. Its totient is φ = 131202222423478.

The previous prime is 131202222423403. The next prime is 131202222423527. The reversal of 131202222423479 is 974324222202131.

It is a strong prime.

It is an emirp because it is prime and its reverse (974324222202131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131202222423479 - 224 = 131202205646263 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131202222453479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601111211739 + 65601111211740.

It is an arithmetic number, because the mean of its divisors is an integer number (65601111211740).

Almost surely, 2131202222423479 is an apocalyptic number.

131202222423479 is a deficient number, since it is larger than the sum of its proper divisors (1).

131202222423479 is an equidigital number, since it uses as much as digits as its factorization.

131202222423479 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 580608, while the sum is 44.

The spelling of 131202222423479 in words is "one hundred thirty-one trillion, two hundred two billion, two hundred twenty-two million, four hundred twenty-three thousand, four hundred seventy-nine".