Base | Representation |
---|---|
bin | 10011000101111010101… |
… | …010100010111101110111 |
3 | 11122102120010202002010211 |
4 | 103011322222202331313 |
5 | 132444010341431103 |
6 | 2442422434130251 |
7 | 163535103324331 |
oct | 23057252427567 |
9 | 4572503662124 |
10 | 1312022998903 |
11 | 466475862221 |
12 | 192341a20987 |
13 | 96952c52386 |
14 | 47706272451 |
15 | 241de6da36d |
hex | 1317aaa2f77 |
1312022998903 has 2 divisors, whose sum is σ = 1312022998904. Its totient is φ = 1312022998902.
The previous prime is 1312022998883. The next prime is 1312022998943. The reversal of 1312022998903 is 3098992202131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312022998903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312022998943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656011499451 + 656011499452.
It is an arithmetic number, because the mean of its divisors is an integer number (656011499452).
Almost surely, 21312022998903 is an apocalyptic number.
1312022998903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312022998903 is an equidigital number, since it uses as much as digits as its factorization.
1312022998903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 49.
The spelling of 1312022998903 in words is "one trillion, three hundred twelve billion, twenty-two million, nine hundred ninety-eight thousand, nine hundred three".
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