Base | Representation |
---|---|
bin | 10011000101111010101… |
… | …010100011100111100101 |
3 | 11122102120010202012210201 |
4 | 103011322222203213211 |
5 | 132444010342022243 |
6 | 2442422434150501 |
7 | 163535103335164 |
oct | 23057252434745 |
9 | 4572503665721 |
10 | 1312023001573 |
11 | 466475864229 |
12 | 192341a22431 |
13 | 96952c5365b |
14 | 477062733db |
15 | 241de6db04d |
hex | 1317aaa39e5 |
1312023001573 has 2 divisors, whose sum is σ = 1312023001574. Its totient is φ = 1312023001572.
The previous prime is 1312023001519. The next prime is 1312023001579. The reversal of 1312023001573 is 3751003202131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1248050934244 + 63972067329 = 1117162^2 + 252927^2 .
It is an emirp because it is prime and its reverse (3751003202131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312023001573 - 213 = 1312022993381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312023001579) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656011500786 + 656011500787.
It is an arithmetic number, because the mean of its divisors is an integer number (656011500787).
Almost surely, 21312023001573 is an apocalyptic number.
It is an amenable number.
1312023001573 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312023001573 is an equidigital number, since it uses as much as digits as its factorization.
1312023001573 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 28.
The spelling of 1312023001573 in words is "one trillion, three hundred twelve billion, twenty-three million, one thousand, five hundred seventy-three".
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