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131203042422997 is a prime number
BaseRepresentation
bin11101110101010000010110…
…101111001011000011010101
3122012112212222121120111111111
4131311100112233023003111
5114144112312330013442
61143013502352135021
736431051462446426
oct3565202657130325
9565485877514444
10131203042422997
1138894996a9a796
1212870041537471
135829517288a8c
1424583927b364d
151027d5b407b17
hex775416bcb0d5

131203042422997 has 2 divisors, whose sum is σ = 131203042422998. Its totient is φ = 131203042422996.

The previous prime is 131203042422989. The next prime is 131203042423001. The reversal of 131203042422997 is 799224240302131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129405321917316 + 1797720505681 = 11375646^2 + 1340791^2 .

It is a cyclic number.

It is not a de Polignac number, because 131203042422997 - 23 = 131203042422989 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131203042422997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131203042422967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601521211498 + 65601521211499.

It is an arithmetic number, because the mean of its divisors is an integer number (65601521211499).

Almost surely, 2131203042422997 is an apocalyptic number.

It is an amenable number.

131203042422997 is a deficient number, since it is larger than the sum of its proper divisors (1).

131203042422997 is an equidigital number, since it uses as much as digits as its factorization.

131203042422997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 49.

The spelling of 131203042422997 in words is "one hundred thirty-one trillion, two hundred three billion, forty-two million, four hundred twenty-two thousand, nine hundred ninety-seven".