Base | Representation |
---|---|
bin | 11000011100000100… |
… | …00110000011110111 |
3 | 1020212101012220222002 |
4 | 30032002012003313 |
5 | 203332301111043 |
6 | 10005530125515 |
7 | 643063660601 |
oct | 141602060367 |
9 | 36771186862 |
10 | 13120332023 |
11 | 56230a3707 |
12 | 2661b8089b |
13 | 13112b3a96 |
14 | 8c6730171 |
15 | 51bcc0bb8 |
hex | 30e0860f7 |
13120332023 has 2 divisors, whose sum is σ = 13120332024. Its totient is φ = 13120332022.
The previous prime is 13120332019. The next prime is 13120332041. The reversal of 13120332023 is 32023302131.
It is a weak prime.
It is an emirp because it is prime and its reverse (32023302131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13120332023 - 22 = 13120332019 is a prime.
It is a super-2 number, since 2×131203320232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13120331986 and 13120332004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120332073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560166011 + 6560166012.
It is an arithmetic number, because the mean of its divisors is an integer number (6560166012).
Almost surely, 213120332023 is an apocalyptic number.
13120332023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120332023 is an equidigital number, since it uses as much as digits as its factorization.
13120332023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 13120332023 its reverse (32023302131), we get a palindrome (45143634154).
The spelling of 13120332023 in words is "thirteen billion, one hundred twenty million, three hundred thirty-two thousand, twenty-three".
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