13120342092491 has 2 divisors, whose sum is σ = 13120342092492. Its totient is φ = 13120342092490.

The previous prime is 13120342092467. The next prime is 13120342092493. The reversal of 13120342092491 is 19429024302131.

It is a strong prime.

It is an emirp because it is prime and its reverse (19429024302131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13120342092491 is a prime.

It is a super-2 number, since 2×13120342092491² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13120342092493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13120342092493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560171046245 + 6560171046246.

It is an arithmetic number, because the mean of its divisors is an integer number (6560171046246).

Almost surely, 2^{13120342092491} is an apocalyptic number.

13120342092491 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120342092491 is an equidigital number, since it uses as much as digits as its factorization.

13120342092491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 13120342092491 in words is "thirteen trillion, one hundred twenty billion, three hundred forty-two million, ninety-two thousand, four hundred ninety-one".