Base | Representation |
---|---|
bin | 1011111011101101000101… |
… | …0110011100010001110010 |
3 | 1201110021220020001001102112 |
4 | 2332323101112130101302 |
5 | 3204430430131134442 |
6 | 43523222504445322 |
7 | 2522625213445265 |
oct | 276732126342162 |
9 | 51407806031375 |
10 | 13120342443122 |
11 | 41a9340298462 |
12 | 157a988179842 |
13 | 742320ab1145 |
14 | 335056a2ccdc |
15 | 17b454732082 |
hex | beed159c472 |
13120342443122 has 4 divisors (see below), whose sum is σ = 19680513664686. Its totient is φ = 6560171221560.
The previous prime is 13120342443107. The next prime is 13120342443137. The reversal of 13120342443122 is 22134424302131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13120342443107) and next prime (13120342443137).
It can be written as a sum of positive squares in only one way, i.e., 12439369248601 + 680973194521 = 3526949^2 + 825211^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280085610779 + ... + 3280085610782.
Almost surely, 213120342443122 is an apocalyptic number.
13120342443122 is a deficient number, since it is larger than the sum of its proper divisors (6560171221564).
13120342443122 is an equidigital number, since it uses as much as digits as its factorization.
13120342443122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6560171221563.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 13120342443122 its reverse (22134424302131), we get a palindrome (35254766745253).
The spelling of 13120342443122 in words is "thirteen trillion, one hundred twenty billion, three hundred forty-two million, four hundred forty-three thousand, one hundred twenty-two".
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