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13120342443122 = 26560171221561
BaseRepresentation
bin1011111011101101000101…
…0110011100010001110010
31201110021220020001001102112
42332323101112130101302
53204430430131134442
643523222504445322
72522625213445265
oct276732126342162
951407806031375
1013120342443122
1141a9340298462
12157a988179842
13742320ab1145
14335056a2ccdc
1517b454732082
hexbeed159c472

13120342443122 has 4 divisors (see below), whose sum is σ = 19680513664686. Its totient is φ = 6560171221560.

The previous prime is 13120342443107. The next prime is 13120342443137. The reversal of 13120342443122 is 22134424302131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13120342443107) and next prime (13120342443137).

It can be written as a sum of positive squares in only one way, i.e., 12439369248601 + 680973194521 = 3526949^2 + 825211^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280085610779 + ... + 3280085610782.

Almost surely, 213120342443122 is an apocalyptic number.

13120342443122 is a deficient number, since it is larger than the sum of its proper divisors (6560171221564).

13120342443122 is an equidigital number, since it uses as much as digits as its factorization.

13120342443122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6560171221563.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13120342443122 its reverse (22134424302131), we get a palindrome (35254766745253).

The spelling of 13120342443122 in words is "thirteen trillion, one hundred twenty billion, three hundred forty-two million, four hundred forty-three thousand, one hundred twenty-two".

Divisors: 1 2 6560171221561 13120342443122