1312041121 has 2 divisors, whose sum is σ = 1312041122. Its totient is φ = 1312041120.

The previous prime is 1312041103. The next prime is 1312041139. The reversal of 1312041121 is 1211402131.

It is a balanced prime because it is at equal distance from previous prime (1312041103) and next prime (1312041139).

It can be written as a sum of positive squares in only one way, i.e., 673973521 + 638067600 = 25961^2 + 25260^2 .

It is an emirp because it is prime and its reverse (1211402131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312041121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312041095 and 1312041104.

It is not a weakly prime, because it can be changed into another prime (1312041151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656020560 + 656020561.

It is an arithmetic number, because the mean of its divisors is an integer number (656020561).

Almost surely, 2^1312041121 is an apocalyptic number.

It is an amenable number.

1312041121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312041121 is an equidigital number, since it uses as much as digits as its factorization.

1312041121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1312041121 is about 36222.1081799500. The cubic root of 1312041121 is about 1094.7521720439.

Adding to 1312041121 its reverse (1211402131), we get a palindrome (2523443252).

The spelling of 1312041121 in words is "one billion, three hundred twelve million, forty-one thousand, one hundred twenty-one".