Base | Representation |
---|---|
bin | 1011111011101101010101… |
… | …1101100000010010011001 |
3 | 1201110022002000210121011112 |
4 | 2332323111131200102121 |
5 | 3204431100304402132 |
6 | 43523233410510105 |
7 | 2522630011551563 |
oct | 276732535402231 |
9 | 51408060717145 |
10 | 13120411403417 |
11 | 41a937620933a |
12 | 157a9a7295335 |
13 | 742332177656 |
14 | 335061c60333 |
15 | 17b45a804ab2 |
hex | beed5760499 |
13120411403417 has 2 divisors, whose sum is σ = 13120411403418. Its totient is φ = 13120411403416.
The previous prime is 13120411403371. The next prime is 13120411403423. The reversal of 13120411403417 is 71430411402131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12844797953296 + 275613450121 = 3583964^2 + 524989^2 .
It is a cyclic number.
It is not a de Polignac number, because 13120411403417 - 234 = 13103231534233 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120411403447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560205701708 + 6560205701709.
It is an arithmetic number, because the mean of its divisors is an integer number (6560205701709).
Almost surely, 213120411403417 is an apocalyptic number.
It is an amenable number.
13120411403417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120411403417 is an equidigital number, since it uses as much as digits as its factorization.
13120411403417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 13120411403417 its reverse (71430411402131), we get a palindrome (84550822805548).
The spelling of 13120411403417 in words is "thirteen trillion, one hundred twenty billion, four hundred eleven million, four hundred three thousand, four hundred seventeen".
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