Base | Representation |
---|---|
bin | 1011111011101101011011… |
… | …0000010100001111101011 |
3 | 1201110022010112122111210201 |
4 | 2332323112300110033223 |
5 | 3204431121334041133 |
6 | 43523235504053031 |
7 | 2522630364225205 |
oct | 276732660241753 |
9 | 51408115574721 |
10 | 13120433112043 |
11 | 41a9387496354 |
12 | 157a9b2604177 |
13 | 7423368086aa |
14 | 335064ab1775 |
15 | 17b45c691d7d |
hex | beed6c143eb |
13120433112043 has 2 divisors, whose sum is σ = 13120433112044. Its totient is φ = 13120433112042.
The previous prime is 13120433112013. The next prime is 13120433112067. The reversal of 13120433112043 is 34021133402131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13120433112043 - 225 = 13120399557611 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120433112013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560216556021 + 6560216556022.
It is an arithmetic number, because the mean of its divisors is an integer number (6560216556022).
Almost surely, 213120433112043 is an apocalyptic number.
13120433112043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120433112043 is an equidigital number, since it uses as much as digits as its factorization.
13120433112043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13120433112043 its reverse (34021133402131), we get a palindrome (47141566514174).
The spelling of 13120433112043 in words is "thirteen trillion, one hundred twenty billion, four hundred thirty-three million, one hundred twelve thousand, forty-three".
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