Base | Representation |
---|---|
bin | 1011111011101101011011… |
… | …0000010100001111001101 |
3 | 1201110022010112122111202121 |
4 | 2332323112300110033031 |
5 | 3204431121334041023 |
6 | 43523235504052541 |
7 | 2522630364225133 |
oct | 276732660241715 |
9 | 51408115574677 |
10 | 13120433112013 |
11 | 41a9387496327 |
12 | 157a9b2604151 |
13 | 742336808686 |
14 | 335064ab1753 |
15 | 17b45c691d5d |
hex | beed6c143cd |
13120433112013 has 2 divisors, whose sum is σ = 13120433112014. Its totient is φ = 13120433112012.
The previous prime is 13120433111923. The next prime is 13120433112043. The reversal of 13120433112013 is 31021133402131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7669338193449 + 5451094918564 = 2769357^2 + 2334758^2 .
It is a cyclic number.
It is not a de Polignac number, because 13120433112013 - 233 = 13111843177421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120433112043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560216556006 + 6560216556007.
It is an arithmetic number, because the mean of its divisors is an integer number (6560216556007).
Almost surely, 213120433112013 is an apocalyptic number.
It is an amenable number.
13120433112013 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120433112013 is an equidigital number, since it uses as much as digits as its factorization.
13120433112013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13120433112013 its reverse (31021133402131), we get a palindrome (44141566514144).
The spelling of 13120433112013 in words is "thirteen trillion, one hundred twenty billion, four hundred thirty-three million, one hundred twelve thousand, thirteen".
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