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13120442737 is a prime number
BaseRepresentation
bin11000011100000101…
…00001000101110001
31020212101102112211121
430032002201011301
5203332313131422
610005532342241
7643064631433
oct141602410561
936771375747
1013120442737
115623169906
122662014981
1313113222ac
148c675c653
1551bce38c7
hex30e0a1171

13120442737 has 2 divisors, whose sum is σ = 13120442738. Its totient is φ = 13120442736.

The previous prime is 13120442707. The next prime is 13120442773. The reversal of 13120442737 is 73724402131.

Together with next prime (13120442773) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9231174241 + 3889268496 = 96079^2 + 62364^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13120442737 is a prime.

It is a super-2 number, since 2×131204427372 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13120442707) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560221368 + 6560221369.

It is an arithmetic number, because the mean of its divisors is an integer number (6560221369).

Almost surely, 213120442737 is an apocalyptic number.

It is an amenable number.

13120442737 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120442737 is an equidigital number, since it uses as much as digits as its factorization.

13120442737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28224, while the sum is 34.

Adding to 13120442737 its reverse (73724402131), we get a palindrome (86844844868).

The spelling of 13120442737 in words is "thirteen billion, one hundred twenty million, four hundred forty-two thousand, seven hundred thirty-seven".