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131206223505127 is a prime number
BaseRepresentation
bin11101110101010011010100…
…010110000010011011100111
3122012120012012022100012211011
4131311103110112002123213
5114144140321204131002
61143015150145523051
736431223350265361
oct3565232426023347
9565505168305734
10131206223505127
11388962796a1891
121287078a943487
1358299033328b4
1424585b5075d31
151027e9581a8d7
hex7754d45826e7

131206223505127 has 2 divisors, whose sum is σ = 131206223505128. Its totient is φ = 131206223505126.

The previous prime is 131206223505121. The next prime is 131206223505191. The reversal of 131206223505127 is 721505322602131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131206223505127 - 211 = 131206223503079 is a prime.

It is a super-4 number, since 4×1312062235051274 (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 131206223505127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131206223505121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65603111752563 + 65603111752564.

It is an arithmetic number, because the mean of its divisors is an integer number (65603111752564).

Almost surely, 2131206223505127 is an apocalyptic number.

131206223505127 is a deficient number, since it is larger than the sum of its proper divisors (1).

131206223505127 is an equidigital number, since it uses as much as digits as its factorization.

131206223505127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 40.

The spelling of 131206223505127 in words is "one hundred thirty-one trillion, two hundred six billion, two hundred twenty-three million, five hundred five thousand, one hundred twenty-seven".