Base | Representation |
---|---|
bin | 10011000101111111010… |
… | …001000110000101110111 |
3 | 11122102202112000222010022 |
4 | 103011333101012011313 |
5 | 132444140123304421 |
6 | 2442434233115355 |
7 | 163540031535542 |
oct | 23057721060567 |
9 | 4572675028108 |
10 | 1312100213111 |
11 | 466505400416 |
12 | 192363858b5b |
13 | 96965c4875c |
14 | 47712611859 |
15 | 241e638d7ab |
hex | 1317f446177 |
1312100213111 has 2 divisors, whose sum is σ = 1312100213112. Its totient is φ = 1312100213110.
The previous prime is 1312100213101. The next prime is 1312100213131. The reversal of 1312100213111 is 1113120012131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312100213111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1312100213111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312100213101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656050106555 + 656050106556.
It is an arithmetic number, because the mean of its divisors is an integer number (656050106556).
Almost surely, 21312100213111 is an apocalyptic number.
1312100213111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312100213111 is an equidigital number, since it uses as much as digits as its factorization.
1312100213111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1312100213111 its reverse (1113120012131), we get a palindrome (2425220225242).
The spelling of 1312100213111 in words is "one trillion, three hundred twelve billion, one hundred million, two hundred thirteen thousand, one hundred eleven".
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