Base | Representation |
---|---|
bin | 1011111011101111100011… |
… | …1101001011000100111011 |
3 | 1201110100121112100100110222 |
4 | 2332323320331023010323 |
5 | 3204433310232021312 |
6 | 43523412442330255 |
7 | 2522650532344646 |
oct | 276737075130473 |
9 | 51410545310428 |
10 | 13121006907707 |
11 | 41a9651376546 |
12 | 157ab327b998b |
13 | 7423c865ab5a |
14 | 3350bad96a5d |
15 | 17b492c35672 |
hex | beef8f4b13b |
13121006907707 has 2 divisors, whose sum is σ = 13121006907708. Its totient is φ = 13121006907706.
The previous prime is 13121006907683. The next prime is 13121006907719. The reversal of 13121006907707 is 70770960012131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13121006907707 - 232 = 13116711940411 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121006907787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560503453853 + 6560503453854.
It is an arithmetic number, because the mean of its divisors is an integer number (6560503453854).
Almost surely, 213121006907707 is an apocalyptic number.
13121006907707 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121006907707 is an equidigital number, since it uses as much as digits as its factorization.
13121006907707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 111132, while the sum is 44.
Adding to 13121006907707 its reverse (70770960012131), we get a palindrome (83891966919838).
The spelling of 13121006907707 in words is "thirteen trillion, one hundred twenty-one billion, six million, nine hundred seven thousand, seven hundred seven".
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