Base | Representation |
---|---|
bin | 11101110101010110111011… |
… | …011101101000000110000100 |
3 | 122012120120012112120221202122 |
4 | 131311112323131220012010 |
5 | 114144221241331000200 |
6 | 1143021031022425112 |
7 | 36431421422565404 |
oct | 3565267335500604 |
9 | 565516175527678 |
10 | 131210101031300 |
11 | 38897989434675 |
12 | 12871491432198 |
13 | 582a0a0772395 |
14 | 2458862028804 |
15 | 1028120e4c385 |
hex | 7755bb768184 |
131210101031300 has 72 divisors (see below), whose sum is σ = 285958287435744. Its totient is φ = 52257240771840.
The previous prime is 131210101031281. The next prime is 131210101031351. The reversal of 131210101031300 is 3130101012131.
It is a super-2 number, since 2×1312101010313002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26485247 + ... + 31046553.
It is an arithmetic number, because the mean of its divisors is an integer number (3971642881052).
Almost surely, 2131210101031300 is an apocalyptic number.
131210101031300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131210101031300 is an abundant number, since it is smaller than the sum of its proper divisors (154748186404444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131210101031300 is a wasteful number, since it uses less digits than its factorization.
131210101031300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4562565 (or 4562558 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 131210101031300 its reverse (3130101012131), we get a palindrome (134340202043431).
The spelling of 131210101031300 in words is "one hundred thirty-one trillion, two hundred ten billion, one hundred one million, thirty-one thousand, three hundred".
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