131210113 has 2 divisors, whose sum is σ = 131210114. Its totient is φ = 131210112.

The previous prime is 131210111. The next prime is 131210137. The reversal of 131210113 is 311012131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95413824 + 35796289 = 9768^2 + 5983^2 .

It is a cyclic number.

It is not a de Polignac number, because 131210113 - 2¹ = 131210111 is a prime.

Together with 131210111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 131210093 and 131210102.

It is not a weakly prime, because it can be changed into another prime (131210111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605056 + 65605057.

It is an arithmetic number, because the mean of its divisors is an integer number (65605057).

Almost surely, 2^131210113 is an apocalyptic number.

It is an amenable number.

131210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210113 is an equidigital number, since it uses as much as digits as its factorization.

131210113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 131210113 is about 11454.6982937134. The cubic root of 131210113 is about 508.1466925547.

Adding to 131210113 its reverse (311012131), we get a palindrome (442222244).

The spelling of 131210113 in words is "one hundred thirty-one million, two hundred ten thousand, one hundred thirteen".