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131210113231 is a prime number
BaseRepresentation
bin111101000110010111…
…0110111000011001111
3110112200020222100220101
41322030232313003033
54122204242110411
6140135504031531
712323336363161
oct1721456670317
9415606870811
10131210113231
115071176310a
122151a0025a7
13c4b07ca272
1464ca0ac931
15362e1ea8c1
hex1e8cbb70cf

131210113231 has 2 divisors, whose sum is σ = 131210113232. Its totient is φ = 131210113230.

The previous prime is 131210113187. The next prime is 131210113241. The reversal of 131210113231 is 132311012131.

It is a strong prime.

It is an emirp because it is prime and its reverse (132311012131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131210113231 - 211 = 131210111183 is a prime.

It is a super-2 number, since 2×1312101132312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131210113199 and 131210113208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131210113241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605056615 + 65605056616.

It is an arithmetic number, because the mean of its divisors is an integer number (65605056616).

Almost surely, 2131210113231 is an apocalyptic number.

131210113231 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210113231 is an equidigital number, since it uses as much as digits as its factorization.

131210113231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 131210113231 its reverse (132311012131), we get a palindrome (263521125362).

The spelling of 131210113231 in words is "one hundred thirty-one billion, two hundred ten million, one hundred thirteen thousand, two hundred thirty-one".