Base | Representation |
---|---|
bin | 10011000101111111011… |
… | …011110001011010101001 |
3 | 11122102202201022011111012 |
4 | 103011333123301122221 |
5 | 132444141332341014 |
6 | 2442434413113305 |
7 | 163540064403566 |
oct | 23057733613251 |
9 | 4572681264435 |
10 | 1312103012009 |
11 | 466506a42259 |
12 | 192364788835 |
13 | 969666b86ca |
14 | 47712b3d86d |
15 | 241e6742c3e |
hex | 1317f6f16a9 |
1312103012009 has 2 divisors, whose sum is σ = 1312103012010. Its totient is φ = 1312103012008.
The previous prime is 1312103011993. The next prime is 1312103012029. The reversal of 1312103012009 is 9002103012131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1295681358400 + 16421653609 = 1138280^2 + 128147^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312103012009 - 24 = 1312103011993 is a prime.
It is a super-2 number, since 2×13121030120092 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1312103012029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656051506004 + 656051506005.
It is an arithmetic number, because the mean of its divisors is an integer number (656051506005).
Almost surely, 21312103012009 is an apocalyptic number.
It is an amenable number.
1312103012009 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312103012009 is an equidigital number, since it uses as much as digits as its factorization.
1312103012009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 1312103012009 in words is "one trillion, three hundred twelve billion, one hundred three million, twelve thousand, nine".
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