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1312103011993 is a prime number
BaseRepresentation
bin10011000101111111011…
…011110001011010011001
311122102202201022011110121
4103011333123301122121
5132444141332340433
62442434413113241
7163540064403544
oct23057733613231
94572681264417
101312103011993
11466506a42244
12192364788821
13969666b86b7
1447712b3d85b
15241e6742c2d
hex1317f6f1699

1312103011993 has 2 divisors, whose sum is σ = 1312103011994. Its totient is φ = 1312103011992.

The previous prime is 1312103011949. The next prime is 1312103012009. The reversal of 1312103011993 is 3991103012131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1185130517769 + 126972494224 = 1088637^2 + 356332^2 .

It is an emirp because it is prime and its reverse (3991103012131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312103011993 - 29 = 1312103011481 is a prime.

It is a super-2 number, since 2×13121030119932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1312103012993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656051505996 + 656051505997.

It is an arithmetic number, because the mean of its divisors is an integer number (656051505997).

Almost surely, 21312103011993 is an apocalyptic number.

It is an amenable number.

1312103011993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312103011993 is an equidigital number, since it uses as much as digits as its factorization.

1312103011993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4374, while the sum is 34.

The spelling of 1312103011993 in words is "one trillion, three hundred twelve billion, one hundred three million, eleven thousand, nine hundred ninety-three".