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131210320032017 is a prime number
BaseRepresentation
bin11101110101010111001000…
…100001000011000100010001
3122012120120202210200100021022
4131311113020201003010101
5114144222213412011032
61143021104444405225
736431430022220432
oct3565271041030421
9565516683610238
10131210320032017
1138897a910150a6
1212871532846815
13582a106c4ccc5
142458883155489
1510281352ab512
hex7755c8843111

131210320032017 has 2 divisors, whose sum is σ = 131210320032018. Its totient is φ = 131210320032016.

The previous prime is 131210320032007. The next prime is 131210320032073. The reversal of 131210320032017 is 710230023012131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101646643344016 + 29563676688001 = 10081996^2 + 5437249^2 .

It is a cyclic number.

It is not a de Polignac number, because 131210320032017 - 26 = 131210320031953 is a prime.

It is a super-2 number, since 2×1312103200320172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131210320032007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605160016008 + 65605160016009.

It is an arithmetic number, because the mean of its divisors is an integer number (65605160016009).

Almost surely, 2131210320032017 is an apocalyptic number.

It is an amenable number.

131210320032017 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210320032017 is an equidigital number, since it uses as much as digits as its factorization.

131210320032017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 131210320032017 its reverse (710230023012131), we get a palindrome (841440343044148).

The spelling of 131210320032017 in words is "one hundred thirty-one trillion, two hundred ten billion, three hundred twenty million, thirty-two thousand, seventeen".