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131210320032007 is a prime number
BaseRepresentation
bin11101110101010111001000…
…100001000011000100000111
3122012120120202210200100020221
4131311113020201003010013
5114144222213412011012
61143021104444405211
736431430022220416
oct3565271041030407
9565516683610227
10131210320032007
1138897a91015097
1212871532846807
13582a106c4ccb8
14245888315547d
1510281352ab507
hex7755c8843107

131210320032007 has 2 divisors, whose sum is σ = 131210320032008. Its totient is φ = 131210320032006.

The previous prime is 131210320031953. The next prime is 131210320032017. The reversal of 131210320032007 is 700230023012131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131210320032007 - 219 = 131210319507719 is a prime.

It is a super-2 number, since 2×1312103200320072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131210320032017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605160016003 + 65605160016004.

It is an arithmetic number, because the mean of its divisors is an integer number (65605160016004).

Almost surely, 2131210320032007 is an apocalyptic number.

131210320032007 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210320032007 is an equidigital number, since it uses as much as digits as its factorization.

131210320032007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 131210320032007 its reverse (700230023012131), we get a palindrome (831440343044138).

The spelling of 131210320032007 in words is "one hundred thirty-one trillion, two hundred ten billion, three hundred twenty million, thirty-two thousand, seven".