Base | Representation |
---|---|
bin | 11101110101010111001000… |
… | …100001000011000100000111 |
3 | 122012120120202210200100020221 |
4 | 131311113020201003010013 |
5 | 114144222213412011012 |
6 | 1143021104444405211 |
7 | 36431430022220416 |
oct | 3565271041030407 |
9 | 565516683610227 |
10 | 131210320032007 |
11 | 38897a91015097 |
12 | 12871532846807 |
13 | 582a106c4ccb8 |
14 | 245888315547d |
15 | 10281352ab507 |
hex | 7755c8843107 |
131210320032007 has 2 divisors, whose sum is σ = 131210320032008. Its totient is φ = 131210320032006.
The previous prime is 131210320031953. The next prime is 131210320032017. The reversal of 131210320032007 is 700230023012131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131210320032007 - 219 = 131210319507719 is a prime.
It is a super-2 number, since 2×1312103200320072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131210320032017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605160016003 + 65605160016004.
It is an arithmetic number, because the mean of its divisors is an integer number (65605160016004).
Almost surely, 2131210320032007 is an apocalyptic number.
131210320032007 is a deficient number, since it is larger than the sum of its proper divisors (1).
131210320032007 is an equidigital number, since it uses as much as digits as its factorization.
131210320032007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 131210320032007 its reverse (700230023012131), we get a palindrome (831440343044138).
The spelling of 131210320032007 in words is "one hundred thirty-one trillion, two hundred ten billion, three hundred twenty million, thirty-two thousand, seven".
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