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131210320187 is a prime number
BaseRepresentation
bin111101000110010111…
…1101001100100111011
3110112200021100212210102
41322030233221210323
54122204320221222
6140135512310015
712323341214432
oct1721457514473
9415607325712
10131210320187
1150711894651
122151a0a230b
13c4b087051b
1464ca124119
15362e23bd92
hex1e8cbe993b

131210320187 has 2 divisors, whose sum is σ = 131210320188. Its totient is φ = 131210320186.

The previous prime is 131210320169. The next prime is 131210320211. The reversal of 131210320187 is 781023012131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131210320187 is a prime.

It is a super-2 number, since 2×1312103201872 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131210320387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605160093 + 65605160094.

It is an arithmetic number, because the mean of its divisors is an integer number (65605160094).

Almost surely, 2131210320187 is an apocalyptic number.

131210320187 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210320187 is an equidigital number, since it uses as much as digits as its factorization.

131210320187 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 29.

The spelling of 131210320187 in words is "one hundred thirty-one billion, two hundred ten million, three hundred twenty thousand, one hundred eighty-seven".