Base | Representation |
---|---|
bin | 111101000110010111… |
… | …1101001100101010011 |
3 | 110112200021100212211022 |
4 | 1322030233221211103 |
5 | 4122204320221321 |
6 | 140135512310055 |
7 | 12323341214465 |
oct | 1721457514523 |
9 | 415607325738 |
10 | 131210320211 |
11 | 50711894673 |
12 | 2151a0a232b |
13 | c4b0870539 |
14 | 64ca124135 |
15 | 362e23bdab |
hex | 1e8cbe9953 |
131210320211 has 2 divisors, whose sum is σ = 131210320212. Its totient is φ = 131210320210.
The previous prime is 131210320187. The next prime is 131210320223. The reversal of 131210320211 is 112023012131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131210320211 is a prime.
It is a super-2 number, since 2×1312103202112 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131210320211.
It is not a weakly prime, because it can be changed into another prime (131210320291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605160105 + 65605160106.
It is an arithmetic number, because the mean of its divisors is an integer number (65605160106).
Almost surely, 2131210320211 is an apocalyptic number.
131210320211 is a deficient number, since it is larger than the sum of its proper divisors (1).
131210320211 is an equidigital number, since it uses as much as digits as its factorization.
131210320211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 131210320211 its reverse (112023012131), we get a palindrome (243233332342).
The spelling of 131210320211 in words is "one hundred thirty-one billion, two hundred ten million, three hundred twenty thousand, two hundred eleven".
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