Base | Representation |
---|---|
bin | 1011111011101111111010… |
… | …0100100001111101001101 |
3 | 1201110100212002121101021011 |
4 | 2332323332210201331031 |
5 | 3204434003341023432 |
6 | 43523430045405221 |
7 | 2522653055145316 |
oct | 276737644417515 |
9 | 51410762541234 |
10 | 13121101111117 |
11 | 41a969a5689aa |
12 | 157ab5a269811 |
13 | 74241202210c |
14 | 3350c96b960d |
15 | 17b49b142847 |
hex | beefe921f4d |
13121101111117 has 2 divisors, whose sum is σ = 13121101111118. Its totient is φ = 13121101111116.
The previous prime is 13121101111093. The next prime is 13121101111199. The reversal of 13121101111117 is 71111110112131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12431505395556 + 689595715561 = 3525834^2 + 830419^2 .
It is a cyclic number.
It is not a de Polignac number, because 13121101111117 - 219 = 13121100586829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121101112117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560550555558 + 6560550555559.
It is an arithmetic number, because the mean of its divisors is an integer number (6560550555559).
Almost surely, 213121101111117 is an apocalyptic number.
It is an amenable number.
13121101111117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121101111117 is an equidigital number, since it uses as much as digits as its factorization.
13121101111117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 22.
Adding to 13121101111117 its reverse (71111110112131), we get a palindrome (84232211223248).
The spelling of 13121101111117 in words is "thirteen trillion, one hundred twenty-one billion, one hundred one million, one hundred eleven thousand, one hundred seventeen".
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