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13121101181 is a prime number
BaseRepresentation
bin11000011100001010…
…00001110101111101
31020212102200000001102
430032011001311331
5203333000214211
610005554422445
7643103343206
oct141605016575
936772600042
1013121101181
115623579581
122662291a25
1313114c2bc6
148c68905ad
1551bdc3a3b
hex30e141d7d

13121101181 has 2 divisors, whose sum is σ = 13121101182. Its totient is φ = 13121101180.

The previous prime is 13121101171. The next prime is 13121101229. The reversal of 13121101181 is 18110112131.

13121101181 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6668192281 + 6452908900 = 81659^2 + 80330^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121101181 is a prime.

It is a super-2 number, since 2×131211011812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121101121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560550590 + 6560550591.

It is an arithmetic number, because the mean of its divisors is an integer number (6560550591).

Almost surely, 213121101181 is an apocalyptic number.

It is an amenable number.

13121101181 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121101181 is an equidigital number, since it uses as much as digits as its factorization.

13121101181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 20.

The spelling of 13121101181 in words is "thirteen billion, one hundred twenty-one million, one hundred one thousand, one hundred eighty-one".