13121101222 has 4 divisors (see below), whose sum is σ = 19681651836. Its totient is φ = 6560550610.

The previous prime is 13121101181. The next prime is 13121101229. The reversal of 13121101222 is 22210112131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 22210112131 = 38461 ⋅577471.

It is a junction number, because it is equal to n+sod(n) for n = 13121101196 and 13121101205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121101229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280275304 + ... + 3280275307.

It is an arithmetic number, because the mean of its divisors is an integer number (4920412959).

Almost surely, 2^13121101222 is an apocalyptic number.

13121101222 is a deficient number, since it is larger than the sum of its proper divisors (6560550614).

13121101222 is an equidigital number, since it uses as much as digits as its factorization.

13121101222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6560550613.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13121101222 its reverse (22210112131), we get a palindrome (35331213353).

The spelling of 13121101222 in words is "thirteen billion, one hundred twenty-one million, one hundred one thousand, two hundred twenty-two".