Search a number
-
+
131211130020301 is a prime number
BaseRepresentation
bin11101110101010111111000…
…110010111010000111001101
3122012120122212020211000022101
4131311113320302322013031
5114144230343241122201
61143021321101315101
736431456056054342
oct3565277062720715
9565518766730271
10131211130020301
1138898367258301
1212871719b65a91
13582a2059bc306
14245891c9607c9
151028181457d01
hex7755f8cba1cd

131211130020301 has 2 divisors, whose sum is σ = 131211130020302. Its totient is φ = 131211130020300.

The previous prime is 131211130020293. The next prime is 131211130020353. The reversal of 131211130020301 is 103020031112131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126597354899401 + 4613775120900 = 11251549^2 + 2147970^2 .

It is a cyclic number.

It is not a de Polignac number, because 131211130020301 - 23 = 131211130020293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131211130020101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605565010150 + 65605565010151.

It is an arithmetic number, because the mean of its divisors is an integer number (65605565010151).

Almost surely, 2131211130020301 is an apocalyptic number.

It is an amenable number.

131211130020301 is a deficient number, since it is larger than the sum of its proper divisors (1).

131211130020301 is an equidigital number, since it uses as much as digits as its factorization.

131211130020301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 131211130020301 its reverse (103020031112131), we get a palindrome (234231161132432).

The spelling of 131211130020301 in words is "one hundred thirty-one trillion, two hundred eleven billion, one hundred thirty million, twenty thousand, three hundred one".