131211210000067 has 2 divisors, whose sum is σ = 131211210000068. Its totient is φ = 131211210000066.

The previous prime is 131211210000061. The next prime is 131211210000071. The reversal of 131211210000067 is 760000012112131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131211210000067 - 2⁷ = 131211209999939 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131211209999996 and 131211210000050.

It is not a weakly prime, because it can be changed into another prime (131211210000061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605605000033 + 65605605000034.

It is an arithmetic number, because the mean of its divisors is an integer number (65605605000034).

Almost surely, 2^{131211210000067} is an apocalyptic number.

131211210000067 is a deficient number, since it is larger than the sum of its proper divisors (1).

131211210000067 is an equidigital number, since it uses as much as digits as its factorization.

131211210000067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 131211210000067 its reverse (760000012112131), we get a palindrome (891211222112198).

The spelling of 131211210000067 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred ten million, sixty-seven", and thus it is an aban number.