131211210000402 has 24 divisors (see below), whose sum is σ = 324903948572736. Its totient is φ = 37488917142936.

The previous prime is 131211210000391. The next prime is 131211210000413. The reversal of 131211210000402 is 204000012112131.

131211210000402 is a `hidden beast` number, since 1 + 31 + 21 + 1 + 210 + 0 + 0 + 0 + 402 = 666.

It is an interprime number because it is at equal distance from previous prime (131211210000391) and next prime (131211210000413).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 520679404638 + ... + 520679404889.

It is an arithmetic number, because the mean of its divisors is an integer number (13537664523864).

Almost surely, 2^{131211210000402} is an apocalyptic number.

131211210000402 is an abundant number, since it is smaller than the sum of its proper divisors (193692738572334).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131211210000402 is a wasteful number, since it uses less digits than its factorization.

131211210000402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1041358809542 (or 1041358809539 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 131211210000402 its reverse (204000012112131), we get a palindrome (335211222112533).

The spelling of 131211210000402 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred ten million, four hundred two", and thus it is an aban number.