Base | Representation |
---|---|
bin | 111101000110011001… |
… | …1011110001101100011 |
3 | 110112200100020210022102 |
4 | 1322030303132031203 |
5 | 4122210044302321 |
6 | 140135550001015 |
7 | 12323352556664 |
oct | 1721463361543 |
9 | 415610223272 |
10 | 131211322211 |
11 | 50712409472 |
12 | 2151a4a616b |
13 | c4b0b31638 |
14 | 64ca30536b |
15 | 362e388c0b |
hex | 1e8ccde363 |
131211322211 has 2 divisors, whose sum is σ = 131211322212. Its totient is φ = 131211322210.
The previous prime is 131211322199. The next prime is 131211322213. The reversal of 131211322211 is 112223112131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131211322211 - 26 = 131211322147 is a prime.
It is a super-2 number, since 2×1312113222112 (a number of 23 digits) contains 22 as substring.
Together with 131211322213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131211322213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605661105 + 65605661106.
It is an arithmetic number, because the mean of its divisors is an integer number (65605661106).
Almost surely, 2131211322211 is an apocalyptic number.
131211322211 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211322211 is an equidigital number, since it uses as much as digits as its factorization.
131211322211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 20.
Adding to 131211322211 its reverse (112223112131), we get a palindrome (243434434342).
The spelling of 131211322211 in words is "one hundred thirty-one billion, two hundred eleven million, three hundred twenty-two thousand, two hundred eleven".
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