Base | Representation |
---|---|
bin | 10011000110000000000… |
… | …011000001001000110111 |
3 | 11122102210102122211222202 |
4 | 103012000003001020313 |
5 | 132444202001100043 |
6 | 2442435421415115 |
7 | 163540251013031 |
oct | 23060003011067 |
9 | 4572712584882 |
10 | 1312113300023 |
11 | 466511829849 |
12 | 19236810a49b |
13 | 9696887b3a6 |
14 | 4771425ac51 |
15 | 241e75c61b8 |
hex | 131800c1237 |
1312113300023 has 2 divisors, whose sum is σ = 1312113300024. Its totient is φ = 1312113300022.
The previous prime is 1312113300011. The next prime is 1312113300053. The reversal of 1312113300023 is 3200033112131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312113300023 - 28 = 1312113299767 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312113299968 and 1312113300004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312113300053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656056650011 + 656056650012.
It is an arithmetic number, because the mean of its divisors is an integer number (656056650012).
Almost surely, 21312113300023 is an apocalyptic number.
1312113300023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312113300023 is an equidigital number, since it uses as much as digits as its factorization.
1312113300023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1312113300023 its reverse (3200033112131), we get a palindrome (4512146412154).
The spelling of 1312113300023 in words is "one trillion, three hundred twelve billion, one hundred thirteen million, three hundred thousand, twenty-three".
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