Base | Representation |
---|---|
bin | 1011111011110000000100… |
… | …1000010000111110010011 |
3 | 1201110100222002101001020212 |
4 | 2332330001020100332103 |
5 | 3204434100333030141 |
6 | 43523434221354335 |
7 | 2522654116033436 |
oct | 276740110207623 |
9 | 51410862331225 |
10 | 13121144033171 |
11 | 41a9711814979 |
12 | 157ab707089ab |
13 | 74241ab9c995 |
14 | 3350d128d81d |
15 | 17b49ecc02eb |
hex | bef01210f93 |
13121144033171 has 2 divisors, whose sum is σ = 13121144033172. Its totient is φ = 13121144033170.
The previous prime is 13121144033077. The next prime is 13121144033213. The reversal of 13121144033171 is 17133044112131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13121144033171 - 238 = 12846266126227 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121144033771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560572016585 + 6560572016586.
It is an arithmetic number, because the mean of its divisors is an integer number (6560572016586).
Almost surely, 213121144033171 is an apocalyptic number.
13121144033171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121144033171 is an equidigital number, since it uses as much as digits as its factorization.
13121144033171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 32.
The spelling of 13121144033171 in words is "thirteen trillion, one hundred twenty-one billion, one hundred forty-four million, thirty-three thousand, one hundred seventy-one".
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