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131211545112161 is a prime number
BaseRepresentation
bin11101110101011000010001…
…100010010110111001100001
3122012120200221011212212021222
4131311120101202112321201
5114144232221022042121
61143021430210224425
736431502256223603
oct3565302142267141
9565520834785258
10131211545112161
113889855a5a0a28
1212871814b85115
13582a2709b5cb7
14245895bb33173
1510281a7aed0ab
hex775611896e61

131211545112161 has 2 divisors, whose sum is σ = 131211545112162. Its totient is φ = 131211545112160.

The previous prime is 131211545112083. The next prime is 131211545112187. The reversal of 131211545112161 is 161211545112131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90201366553600 + 41010178558561 = 9497440^2 + 6403919^2 .

It is a cyclic number.

It is not a de Polignac number, because 131211545112161 - 222 = 131211540917857 is a prime.

It is a super-2 number, since 2×1312115451121612 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131211545114161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605772556080 + 65605772556081.

It is an arithmetic number, because the mean of its divisors is an integer number (65605772556081).

Almost surely, 2131211545112161 is an apocalyptic number.

It is an amenable number.

131211545112161 is a deficient number, since it is larger than the sum of its proper divisors (1).

131211545112161 is an equidigital number, since it uses as much as digits as its factorization.

131211545112161 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7200, while the sum is 35.

The spelling of 131211545112161 in words is "one hundred thirty-one trillion, two hundred eleven billion, five hundred forty-five million, one hundred twelve thousand, one hundred sixty-one".