Base | Representation |
---|---|
bin | 11101110101011000010001… |
… | …100010010110111000010011 |
3 | 122012120200221011212212012002 |
4 | 131311120101202112320103 |
5 | 114144232221022041313 |
6 | 1143021430210224215 |
7 | 36431502256223432 |
oct | 3565302142267023 |
9 | 565520834785162 |
10 | 131211545112083 |
11 | 3889855a5a0967 |
12 | 12871814b8506b |
13 | 582a2709b5c57 |
14 | 245895bb33119 |
15 | 10281a7aed058 |
hex | 775611896e13 |
131211545112083 has 2 divisors, whose sum is σ = 131211545112084. Its totient is φ = 131211545112082.
The previous prime is 131211545112029. The next prime is 131211545112161. The reversal of 131211545112083 is 380211545112131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131211545112083 - 28 = 131211545111827 is a prime.
It is not a weakly prime, because it can be changed into another prime (131211545115083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605772556041 + 65605772556042.
It is an arithmetic number, because the mean of its divisors is an integer number (65605772556042).
Almost surely, 2131211545112083 is an apocalyptic number.
131211545112083 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211545112083 is an equidigital number, since it uses as much as digits as its factorization.
131211545112083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 38.
The spelling of 131211545112083 in words is "one hundred thirty-one trillion, two hundred eleven billion, five hundred forty-five million, one hundred twelve thousand, eighty-three".
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