131212001122019 has 2 divisors, whose sum is σ = 131212001122020. Its totient is φ = 131212001122018.

The previous prime is 131212001121997. The next prime is 131212001122021. The reversal of 131212001122019 is 910221100212131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131212001122019 - 2³⁶ = 131143281645283 is a prime.

It is a super-2 number, since 2×131212001122019² (a number of 29 digits) contains 22 as substring.

Together with 131212001122021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131212001122039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606000561009 + 65606000561010.

It is an arithmetic number, because the mean of its divisors is an integer number (65606000561010).

Almost surely, 2^{131212001122019} is an apocalyptic number.

131212001122019 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212001122019 is an equidigital number, since it uses as much as digits as its factorization.

131212001122019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 26.

The spelling of 131212001122019 in words is "one hundred thirty-one trillion, two hundred twelve billion, one million, one hundred twenty-two thousand, nineteen".