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131212021122020 = 2256560601056101
BaseRepresentation
bin11101110101011000101101…
…111010001100001111100100
3122012120202011100120200001202
4131311120231322030033210
5114144234204401401040
61143021545332542032
736431520126232466
oct3565305572141744
9565522140520052
10131212021122020
1138898784262203
1212871928481918
13582a3184bb737
1424589a5042136
1510281d47c8015
hex77562de8c3e4

131212021122020 has 12 divisors (see below), whose sum is σ = 275545244356284. Its totient is φ = 52484808448800.

The previous prime is 131212021121983. The next prime is 131212021122043. The reversal of 131212021122020 is 20221120212131.

It can be written as a sum of positive squares in 2 ways, for example, as 74923704599104 + 56288316522916 = 8655848^2 + 7502554^2 .

It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 6560601056101 = 131212021122020 / (1 + 3 + 1 + 2 + 1 + 2 + 0 + 2 + 1 + 1 + 2 + 2 + 0 + 2 + 0).

It is a junction number, because it is equal to n+sod(n) for n = 131212021121983 and 131212021122001.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3280300528031 + ... + 3280300528070.

It is an arithmetic number, because the mean of its divisors is an integer number (22962103696357).

Almost surely, 2131212021122020 is an apocalyptic number.

131212021122020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131212021122020 is an abundant number, since it is smaller than the sum of its proper divisors (144333223234264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131212021122020 is a wasteful number, since it uses less digits than its factorization.

131212021122020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6560601056110 (or 6560601056108 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 131212021122020 its reverse (20221120212131), we get a palindrome (151433141334151).

The spelling of 131212021122020 in words is "one hundred thirty-one trillion, two hundred twelve billion, twenty-one million, one hundred twenty-two thousand, twenty".

Divisors: 1 2 4 5 10 20 6560601056101 13121202112202 26242404224404 32803005280505 65606010561010 131212021122020