131212021122043 has 2 divisors, whose sum is σ = 131212021122044. Its totient is φ = 131212021122042.

The previous prime is 131212021121983. The next prime is 131212021122073. The reversal of 131212021122043 is 340221120212131.

It is a strong prime.

It is an emirp because it is prime and its reverse (340221120212131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131212021122043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131212021121999 and 131212021122017.

It is not a weakly prime, because it can be changed into another prime (131212021122073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606010561021 + 65606010561022.

It is an arithmetic number, because the mean of its divisors is an integer number (65606010561022).

Almost surely, 2^{131212021122043} is an apocalyptic number.

131212021122043 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212021122043 is an equidigital number, since it uses as much as digits as its factorization.

131212021122043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131212021122043 its reverse (340221120212131), we get a palindrome (471433141334174).

The spelling of 131212021122043 in words is "one hundred thirty-one trillion, two hundred twelve billion, twenty-one million, one hundred twenty-two thousand, forty-three".