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131212024301400 = 233527231379914617
BaseRepresentation
bin11101110101011000101110…
…000110010100011101011000
3122012120202011120120012100120
4131311120232012110131120
5114144234211210121100
61143021545525033240
736431520165244020
oct3565305606243530
9565522146505316
10131212024301400
1138898786033999
1212871929555820
13582a319062923
1424589a562ca80
1510281d4c050a0
hex77562e194758

131212024301400 has 384 divisors, whose sum is σ = 488617756462080. Its totient is φ = 28477949829120.

The previous prime is 131212024301333. The next prime is 131212024301453. The reversal of 131212024301400 is 4103420212131.

131212024301400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 8276892 + ... + 18191508.

It is an arithmetic number, because the mean of its divisors is an integer number (1272442074120).

Almost surely, 2131212024301400 is an apocalyptic number.

131212024301400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131212024301400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (244308878231040).

131212024301400 is an abundant number, since it is smaller than the sum of its proper divisors (357405732160680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131212024301400 is a wasteful number, since it uses less digits than its factorization.

131212024301400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9914803 (or 9914794 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131212024301400 its reverse (4103420212131), we get a palindrome (135315444513531).

The spelling of 131212024301400 in words is "one hundred thirty-one trillion, two hundred twelve billion, twenty-four million, three hundred one thousand, four hundred".