Base | Representation |
---|---|
bin | 10011000110000000011… |
… | …101110101101101111101 |
3 | 11122102210220220001212020 |
4 | 103012000131311231331 |
5 | 132444210301044013 |
6 | 2442440232230353 |
7 | 163540364535633 |
oct | 23060035655575 |
9 | 4572726801766 |
10 | 1312120331133 |
11 | 4665157a1387 |
12 | 19236a53b3b9 |
13 | 9696a170801 |
14 | 4771516b353 |
15 | 241e8014623 |
hex | 13180775b7d |
1312120331133 has 4 divisors (see below), whose sum is σ = 1749493774848. Its totient is φ = 874746887420.
The previous prime is 1312120331117. The next prime is 1312120331233. The reversal of 1312120331133 is 3311330212131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1312120331133 - 24 = 1312120331117 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312120331033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218686721853 + ... + 218686721858.
It is an arithmetic number, because the mean of its divisors is an integer number (437373443712).
Almost surely, 21312120331133 is an apocalyptic number.
It is an amenable number.
1312120331133 is a deficient number, since it is larger than the sum of its proper divisors (437373443715).
1312120331133 is an equidigital number, since it uses as much as digits as its factorization.
1312120331133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437373443714.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 1312120331133 its reverse (3311330212131), we get a palindrome (4623450543264).
The spelling of 1312120331133 in words is "one trillion, three hundred twelve billion, one hundred twenty million, three hundred thirty-one thousand, one hundred thirty-three".
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