Base | Representation |
---|---|
bin | 1011111011110000010100… |
… | …0100101110101000000111 |
3 | 1201110101010200220102112201 |
4 | 2332330011010232220013 |
5 | 3204434214303334134 |
6 | 43523444544055331 |
7 | 2522655551415232 |
oct | 276740504565007 |
9 | 51411120812481 |
10 | 13121210214919 |
11 | 41a9746108234 |
12 | 157ab8a904547 |
13 | 74242b802591 |
14 | 3350d9d9a419 |
15 | 17b4a59e4914 |
hex | bef0512ea07 |
13121210214919 has 2 divisors, whose sum is σ = 13121210214920. Its totient is φ = 13121210214918.
The previous prime is 13121210214911. The next prime is 13121210214943. The reversal of 13121210214919 is 91941201212131.
13121210214919 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121210214919 - 23 = 13121210214911 is a prime.
It is a super-2 number, since 2×131212102149192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121210214911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560605107459 + 6560605107460.
It is an arithmetic number, because the mean of its divisors is an integer number (6560605107460).
Almost surely, 213121210214919 is an apocalyptic number.
13121210214919 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121210214919 is an equidigital number, since it uses as much as digits as its factorization.
13121210214919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 37.
The spelling of 13121210214919 in words is "thirteen trillion, one hundred twenty-one billion, two hundred ten million, two hundred fourteen thousand, nine hundred nineteen".
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