Base | Representation |
---|---|
bin | 10011000110000000100… |
… | …100101011001111000011 |
3 | 11122102211001021010010012 |
4 | 103012000210223033003 |
5 | 132444211230420303 |
6 | 2442440334455135 |
7 | 163540416011423 |
oct | 23060044531703 |
9 | 4572731233105 |
10 | 1312122123203 |
11 | 466516805831 |
12 | 19236b0644ab |
13 | 9696a64a3c8 |
14 | 477154b6483 |
15 | 241e826a5d8 |
hex | 1318092b3c3 |
1312122123203 has 2 divisors, whose sum is σ = 1312122123204. Its totient is φ = 1312122123202.
The previous prime is 1312122123197. The next prime is 1312122123209. The reversal of 1312122123203 is 3023212212131.
It is a balanced prime because it is at equal distance from previous prime (1312122123197) and next prime (1312122123209).
It is an emirp because it is prime and its reverse (3023212212131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312122123203 - 24 = 1312122123187 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312122123209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656061061601 + 656061061602.
It is an arithmetic number, because the mean of its divisors is an integer number (656061061602).
Almost surely, 21312122123203 is an apocalyptic number.
1312122123203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312122123203 is an equidigital number, since it uses as much as digits as its factorization.
1312122123203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 1312122123203 its reverse (3023212212131), we get a palindrome (4335334335334).
The spelling of 1312122123203 in words is "one trillion, three hundred twelve billion, one hundred twenty-two million, one hundred twenty-three thousand, two hundred three".
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