Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …010110001001110001110101 |
3 | 122012120202122201122010222222 |
4 | 131311120321112021301311 |
5 | 114144240103012020313 |
6 | 1143022020345332125 |
7 | 36431524646205422 |
oct | 3565307126116165 |
9 | 565522581563888 |
10 | 131212213001333 |
11 | 388988725a8a52 |
12 | 12871980797045 |
13 | 582a3491916a9 |
14 | 24589c270cd49 |
15 | 10281e657b208 |
hex | 775639589c75 |
131212213001333 has 2 divisors, whose sum is σ = 131212213001334. Its totient is φ = 131212213001332.
The previous prime is 131212213001297. The next prime is 131212213001347. The reversal of 131212213001333 is 333100312212131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 98662244154769 + 32549968846564 = 9932887^2 + 5705258^2 .
It is a cyclic number.
It is not a de Polignac number, because 131212213001333 - 214 = 131212212984949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131212213051333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606106500666 + 65606106500667.
It is an arithmetic number, because the mean of its divisors is an integer number (65606106500667).
Almost surely, 2131212213001333 is an apocalyptic number.
It is an amenable number.
131212213001333 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212213001333 is an equidigital number, since it uses as much as digits as its factorization.
131212213001333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 131212213001333 its reverse (333100312212131), we get a palindrome (464312525213464).
The spelling of 131212213001333 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred thirteen million, one thousand, three hundred thirty-three".
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