Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …010111110000100101000000 |
3 | 122012120202122202102112121001 |
4 | 131311120321113300211000 |
5 | 114144240103114004100 |
6 | 1143022020402341344 |
7 | 36431524652611135 |
oct | 3565307127604500 |
9 | 565522582375531 |
10 | 131212213422400 |
11 | 38898872866340 |
12 | 1287198095a854 |
13 | 582a3492ab246 |
14 | 24589c27bc58c |
15 | 10281e6610d6a |
hex | 7756395f0940 |
131212213422400 has 336 divisors, whose sum is σ = 372230320734720. Its totient is φ = 45022176000000.
The previous prime is 131212213422347. The next prime is 131212213422401. The reversal of 131212213422400 is 4224312212131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131212213422401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 83152765 + ... + 84716035.
It is an arithmetic number, because the mean of its divisors is an integer number (1107828335520).
Almost surely, 2131212213422400 is an apocalyptic number.
131212213422400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131212213422400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (186115160367360).
131212213422400 is an abundant number, since it is smaller than the sum of its proper divisors (241018107312320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131212213422400 is a wasteful number, since it uses less digits than its factorization.
131212213422400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1563574 (or 1563559 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 131212213422400 its reverse (4224312212131), we get a palindrome (135436525634531).
The spelling of 131212213422400 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred thirteen million, four hundred twenty-two thousand, four hundred".
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