Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …111000011110110001110011 |
3 | 122012120202200100120100011221 |
4 | 131311120321320132301303 |
5 | 114144240112313001433 |
6 | 1143022021310245511 |
7 | 36431525115535336 |
oct | 3565307170366163 |
9 | 565522610510157 |
10 | 131212222000243 |
11 | 38898877694a6a |
12 | 128719837b6897 |
13 | 582a34acc26a7 |
14 | 24589c39b261d |
15 | 10281e725772d |
hex | 775639e1ec73 |
131212222000243 has 2 divisors, whose sum is σ = 131212222000244. Its totient is φ = 131212222000242.
The previous prime is 131212222000231. The next prime is 131212222000333. The reversal of 131212222000243 is 342000222212131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131212222000243 is a prime.
It is not a weakly prime, because it can be changed into another prime (131212222004243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606111000121 + 65606111000122.
It is an arithmetic number, because the mean of its divisors is an integer number (65606111000122).
Almost surely, 2131212222000243 is an apocalyptic number.
131212222000243 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212222000243 is an equidigital number, since it uses as much as digits as its factorization.
131212222000243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 131212222000243 its reverse (342000222212131), we get a palindrome (473212444212374).
The spelling of 131212222000243 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred twenty-two million, two hundred forty-three", and thus it is an aban number.
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