Base | Representation |
---|---|
bin | 11101110101011000111010… |
… | …011011010111001110010110 |
3 | 122012120202200222202220112021 |
4 | 131311120322123113032112 |
5 | 114144240122133104332 |
6 | 1143022022234243354 |
7 | 36431525256341455 |
oct | 3565307233271626 |
9 | 565522628686467 |
10 | 131212231144342 |
11 | 38898881870077 |
12 | 1287198688655a |
13 | 582a34cb747ba |
14 | 24589c4cb2b9c |
15 | 10281e7e61c97 |
hex | 77563a6d7396 |
131212231144342 has 16 divisors (see below), whose sum is σ = 197630072337600. Its totient is φ = 65335813263432.
The previous prime is 131212231144331. The next prime is 131212231144433. The reversal of 131212231144342 is 243441132212131.
It is a super-2 number, since 2×1312122311443422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131212231144298 and 131212231144307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67261948 + ... + 69185215.
It is an arithmetic number, because the mean of its divisors is an integer number (12351879521100).
Almost surely, 2131212231144342 is an apocalyptic number.
131212231144342 is a deficient number, since it is larger than the sum of its proper divisors (66417841193258).
131212231144342 is a wasteful number, since it uses less digits than its factorization.
131212231144342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136449147.
The product of its digits is 27648, while the sum is 34.
Adding to 131212231144342 its reverse (243441132212131), we get a palindrome (374653363356473).
The spelling of 131212231144342 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred thirty-one million, one hundred forty-four thousand, three hundred forty-two".
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