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131212241223407 is a prime number
BaseRepresentation
bin11101110101011000111011…
…000001110011111011101111
3122012120202201200201222101222
4131311120323001303323233
5114144240132223122112
61143022023234253555
736431525441120501
oct3565307301637357
9565522650658358
10131212241223407
1138898887524683
121287198a1272bb
13582a351c93346
1424589c6377d71
1510281e8ca3372
hex77563b073eef

131212241223407 has 2 divisors, whose sum is σ = 131212241223408. Its totient is φ = 131212241223406.

The previous prime is 131212241223331. The next prime is 131212241223463. The reversal of 131212241223407 is 704322142212131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131212241223407 - 216 = 131212241157871 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131212241225407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606120611703 + 65606120611704.

It is an arithmetic number, because the mean of its divisors is an integer number (65606120611704).

Almost surely, 2131212241223407 is an apocalyptic number.

131212241223407 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212241223407 is an equidigital number, since it uses as much as digits as its factorization.

131212241223407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 35.

Adding to 131212241223407 its reverse (704322142212131), we get a palindrome (835534383435538).

The spelling of 131212241223407 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred forty-one million, two hundred twenty-three thousand, four hundred seven".