Base | Representation |
---|---|
bin | 11101110101011000111011… |
… | …000001110011111011101111 |
3 | 122012120202201200201222101222 |
4 | 131311120323001303323233 |
5 | 114144240132223122112 |
6 | 1143022023234253555 |
7 | 36431525441120501 |
oct | 3565307301637357 |
9 | 565522650658358 |
10 | 131212241223407 |
11 | 38898887524683 |
12 | 1287198a1272bb |
13 | 582a351c93346 |
14 | 24589c6377d71 |
15 | 10281e8ca3372 |
hex | 77563b073eef |
131212241223407 has 2 divisors, whose sum is σ = 131212241223408. Its totient is φ = 131212241223406.
The previous prime is 131212241223331. The next prime is 131212241223463. The reversal of 131212241223407 is 704322142212131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131212241223407 - 216 = 131212241157871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131212241225407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606120611703 + 65606120611704.
It is an arithmetic number, because the mean of its divisors is an integer number (65606120611704).
Almost surely, 2131212241223407 is an apocalyptic number.
131212241223407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212241223407 is an equidigital number, since it uses as much as digits as its factorization.
131212241223407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 131212241223407 its reverse (704322142212131), we get a palindrome (835534383435538).
The spelling of 131212241223407 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred forty-one million, two hundred twenty-three thousand, four hundred seven".
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