131212313420143 has 2 divisors, whose sum is σ = 131212313420144. Its totient is φ = 131212313420142.

The previous prime is 131212313420129. The next prime is 131212313420183. The reversal of 131212313420143 is 341024313212131.

It is a weak prime.

It is an emirp because it is prime and its reverse (341024313212131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131212313420143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131212313420183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606156710071 + 65606156710072.

It is an arithmetic number, because the mean of its divisors is an integer number (65606156710072).

Almost surely, 2^{131212313420143} is an apocalyptic number.

131212313420143 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212313420143 is an equidigital number, since it uses as much as digits as its factorization.

131212313420143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131212313420143 its reverse (341024313212131), we get a palindrome (472236626632274).

The spelling of 131212313420143 in words is "one hundred thirty-one trillion, two hundred twelve billion, three hundred thirteen million, four hundred twenty thousand, one hundred forty-three".