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131212332049 is a prime number
BaseRepresentation
bin111101000110011011…
…1010100110000010001
3110112200102011002112211
41322030313110300101
54122210324111144
6140140023352121
712323364264061
oct1721467246021
9415612132484
10131212332049
1150712a39147
122151a8b2641
13c4b10c6186
1464ca4c93a1
15362e4d8034
hex1e8cdd4c11

131212332049 has 2 divisors, whose sum is σ = 131212332050. Its totient is φ = 131212332048.

The previous prime is 131212332011. The next prime is 131212332061. The reversal of 131212332049 is 940233212131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123724545025 + 7487787024 = 351745^2 + 86532^2 .

It is an emirp because it is prime and its reverse (940233212131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131212332049 - 213 = 131212323857 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131212332049.

It is not a weakly prime, because it can be changed into another prime (131212332079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606166024 + 65606166025.

It is an arithmetic number, because the mean of its divisors is an integer number (65606166025).

Almost surely, 2131212332049 is an apocalyptic number.

It is an amenable number.

131212332049 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212332049 is an equidigital number, since it uses as much as digits as its factorization.

131212332049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 131212332049 in words is "one hundred thirty-one billion, two hundred twelve million, three hundred thirty-two thousand, forty-nine".