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131212333280243 is a prime number
BaseRepresentation
bin11101110101011001000000…
…100000111110101111110011
3122012120202222002221221122102
4131311121000200332233303
5114144240324304431433
61143022040323331015
736431530636440665
oct3565310040765763
9565522862857572
10131212333280243
1138898924490306
12128719b4b20a6b
13582a368085547
1424589d469c535
151028201dd94e8
hex77564083ebf3

131212333280243 has 2 divisors, whose sum is σ = 131212333280244. Its totient is φ = 131212333280242.

The previous prime is 131212333280239. The next prime is 131212333280299. The reversal of 131212333280243 is 342082333212131.

It is a weak prime.

It is an emirp because it is prime and its reverse (342082333212131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131212333280243 - 22 = 131212333280239 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 131212333280197 and 131212333280206.

It is not a weakly prime, because it can be changed into another prime (131212333280543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606166640121 + 65606166640122.

It is an arithmetic number, because the mean of its divisors is an integer number (65606166640122).

Almost surely, 2131212333280243 is an apocalyptic number.

131212333280243 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212333280243 is an equidigital number, since it uses as much as digits as its factorization.

131212333280243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 38.

Adding to 131212333280243 its reverse (342082333212131), we get a palindrome (473294666492374).

The spelling of 131212333280243 in words is "one hundred thirty-one trillion, two hundred twelve billion, three hundred thirty-three million, two hundred eighty thousand, two hundred forty-three".